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x=\frac{-11±\sqrt{11^{2}-4\times 3\left(-4\right)}}{2\times 3} This equation is in standard form: ax^{2}+bx+c=0. Substitute 3 for a, 11 for b, and -4 for c in the quadratic formula, \frac{ …
Divide 2x^ {4}+x^ {3}-11x^ {2}+x+2 by x-2 to get 2x^ {3}+5x^ {2}-x-1. Solve the equation where the result equals to 0. By Rational Root Theorem, all rational roots of a polynomial are in the form …
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This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, -11 for b, and -3 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
$$\therefore P(x) = 2x^4+x^3-11x^2+x+2 = (x−2)(2x^3+5x^2−x−1)$$ Where $(2x^3+5x^2−x−1)$ can be obtained by either of long division or synthetic division (which is …
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